Patrick Mahomes’ four TD passes gets him this award for the fourth time in his career

Chiefs quarterback Patrick Mahomes put the finishing touches on a stellar Week 3 with league recognition.

Mahomes was chosen the AFC Offensive Player of the Week, the NFL announced Wednesday morning.

The Chiefs’ signal-caller completed 31 of 42 passes for 385 yards and four touchdowns with a 133.5 passer rating, adding 26 yards rushing and a touchdown, to lead Kansas City in a 34-20 win over the Baltimore Ravens.

His scoring passes went to four different players: wide receiver Tyreek Hill, wide receiver Mecole Hardman, fullback Anthony Sherman and left tackle Eric Fisher.

Mahomes’ performance Monday night propelled the Chiefs to a fourth straight 3-0 start to a regular season and their 12th consecutive win combining the regular season and postseason dating back to Week 11 of the 2019 campaign.

He also etched his name in the NFL record books with another notable achievement. Mahomes topped 10,000 career passing yards in just his 34th game to become the fastest quarterback in league history to reach the milestone. Pro Football Hall of Famer Kurt Warner previously set the mark at 36 games.

Wednesday’s announcement marked the fourth time in Mahomes’ career he was won the AFC Offensive Player of the Week. The NFL previously recognized Mahomes with the award twice in 2018 and once in 2019.

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